Factor:
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This expression has two terms. There is a common factor of 2ab. Begin by factoring out the common factor. |
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The remaining factor is a binomial that is the difference of two squares. This factor must be factored using the difference of two squares technique. |
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Each of the new factors must in turn be checked for further factoring. In this case, no further factoring can be done. Our final answer is 2ab(a+11b)(a-11b) |
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Factor:
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This
expression has two terms with no common factor. If it is factorable,
it must be by binomial techniques. In this case
we have the difference of two squares.
Notice that each factor is a binomial. Further factoring may be required. The first factor is the difference of squares and therefore factorable. Factor this factor. The second factor is prime. |
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HINT:
etc.
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No further factoring can be done. Each of the binomials is prime. The final answer, therefore is (a+2b)(a-2b)(a2+4b2) |
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NOTE: Once the binomial factors contain first degree terms, no further factoring will be possible using the binomial techniques. |
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Factor:
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This
expression has three terms. There
is common factor shared by ALL three terms. Factor out the GCF first.
The
remaining trinomial may be factored further.
(4x)(2) +(x)(3)=8x+3x=11x
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NOTE:
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